Carlos4463 Carlos4463
  • 26-08-2020
  • Mathematics
contestada

Use the Well-Ordering Principle to prove that given a > 0, a^n > 0 for every positive integer n

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codiepienagoya codiepienagoya
  • 31-08-2020

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given value:

[tex]\to x > 0[/tex]

[tex]\to S= { n\varepsilon N : x^n \leq 0 } \\\\ s \neq \phi \\\\ \to x^n \leq 0\\[/tex]

[tex]\to x^{n-1} x\leq 0\\\\ \to x>0 = x^{n-1} \leq 0 \\\\\to n-1 \varepsilon s \\ \ \ _{where} \ \ n-1 < n \\\\\to s= \phi \\\\\to \hence x^n > 0 \\[/tex]

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