danito7271
danito7271 danito7271
  • 31-07-2020
  • Mathematics
contestada

represent in polar form 1-i/1+i
​

Respuesta :

LammettHash
LammettHash LammettHash
  • 31-07-2020

We have

[tex]\dfrac{1-i}{1+i}=\dfrac{e^{-i\frac\pi4}}{e^{i\frac\pi4}}=e^{-i\frac\pi2}[/tex]

which reduces to -i.

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