24 and 16
Step-by-step explanation:
let's assume two part be x and (40 - x)
According to Question,
[tex] x\dfrac{1}{4} = (40 - x) \dfrac{3}{8} [/tex]
[tex] x= \dfrac{3(40 - x)}{2} [/tex]
[tex]2 \times x = 120 - 3x [/tex]
[tex]2x + 3x = 120[/tex]
[tex]5x = 120[/tex]
[tex] \cancel{5}x= \cancel{120}[/tex]
[tex]x = 24[/tex]
Hence one part is 24 and other is (40 - 24) = 16 .
