Answer:
[tex]\boxed{\sf \ \ \ x=-5 \ \ \ or \ \ \ x=-1 \ \ }[/tex]
Step-by-step explanation:
[tex]x^2+6x+5 = x^2+x+5x+5 = x(x+1)+5(x+1)=(x+5)(x+1)[/tex]
so
[tex]x^2+6x+5 = 0 <=> (x+5)(x+1)=0\\\\<=> x = -5 \ or \ x=-1[/tex]
hope this helps
