Answer:
[tex]d=2\sqrt{5}[/tex] units
Step-by-step explanation:
[tex]\text{Distance, }d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$If ( x_1 , y_1 ) = ( 0 , - 5 )$ and ( x_2 , y_2 ) = ( 4 , - 3 )\\\\d=\sqrt{(4-0)^2+(-3-(-5))^2} \\=\sqrt{4^2+(-3+5)^2}\\=\sqrt{4^2+2^2}\\=\sqrt{20}\\\\d=2\sqrt{5}$ units[/tex]
