Respuesta :

braintliess387

Answer:

he trigonometric ( or polar) form of  z= a+bi is z = r(cosθ+isinθ) .

So for Part 3  3 - 3i we have r = √(3^2 + (-3)^2) = 3√2 and θ= arctan(3/-3) = arctan (-1) = -π/4.

So the answer is  3√2(cos(-π/4) + isin(-π/4).

Part 1.  3 =  3(cos 0 - i sin 0).

Part 2.  -6i =  6(cos (-π/2) - isin -(π/2)

Step-by-step explanation:

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