Answer: There are [tex]4.81\times 10^{23}[/tex] molecules in 0.80 mol of NaCl.
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
As 1 mole of [tex]NaCl[/tex] contains = [tex]6.023\times 10^{23}[/tex] molecules
0.80 mole of [tex]NaCl[/tex] contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.80=4.81\times 10^{23}[/tex] molecules
Thus there are [tex]4.81\times 10^{23}[/tex] molecules in 0.80 mol of NaCl.
