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  • 30-04-2020
  • Mathematics
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The interior angles of a quadrilateral are 2x+15 2x-5 3x+75 3x-25 find x and the smallest interior angle largest interior angle and smallest exterior angle

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nuuk nuuk
  • 30-04-2020

Answer:[tex]x=30^{\circ}[/tex]

Step-by-step explanation:

We know sum of the interior angles of a quadrilateral is [tex]360^{\circ}[/tex]

therefore  we can write

[tex](2x+15)+(2x-5)+(3x+75)+(3x-25)=360^{\circ}[/tex]

so

[tex]\Rightarrow 10x+60=360[/tex]

[tex]\Rightarrow 10x=300[/tex]

[tex]\Rightarrow x=30^{\circ}[/tex]

So smallest interior angle is [tex](2x-5)^{\circ}=(60-5)=55^{\circ}[/tex]

Largest interior angle [tex]=3x+75=90+75=165^{\circ}[/tex]

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