pamelawuzhere pamelawuzhere
  • 27-04-2020
  • Mathematics
contestada

Find the distance and midpoint between (- 8, 1) and (4, 6)

Respuesta :

nicole2023276
nicole2023276 nicole2023276
  • 27-04-2020

Answer:

Distance: 13, Midpoint: (-2, 3.5)

Step-by-step explanation:

The distance formula is [tex]\sqrt{(x2-x1)^{2} +(y2-y1)^{2} }[/tex]. We can plug in the numbers from your question so it would be √(4+8)^2+(6-1)^2 =  √144+25=169 =√169 = 13

The midpoint formula is ((x1+x2)/2, (y1+y2)/2), which is -8+4/2, 1+6/2 = (-2, 3.5).

Answer Link

Otras preguntas

prove that [tex]cos 9x-cos 5x/sin17x-sin3x=-sin2x/cos10x[/tex]
What does trajectory mean?
How do you figure out this word problem: Peter has 6 sweaters, 4 pairs of jeans and 3 pairs of shoes. How many outfits can Peter make?
What In algebra, find the slope of x+3y=6?
What is 7x squared-2x+5?
what is the answer 3.5r=3(4+.5r)?
I throw a stone off a cliff 32 feet above the water.  The height of the stone in terms of time (in seconds) is given by h(t) = -16t2 + 128t + 32.  At what time
What In algebra, find the slope of x+3y=6?
round 2.6 to the nearest tenth
Help me with this question please thank you A ball is thrown downward from a window from a tall building. Its position at time t in seconds is s = 16t^2 + 32t,