sweedensiutoung sweedensiutoung
  • 31-03-2020
  • Mathematics
contestada

(b+10) (b^3+6b^2-32b+78)

Respuesta :

amna04352
amna04352 amna04352
  • 31-03-2020

Answer:

b⁴ + 16b³ + 28b² - 242b + 780

Step-by-step explanation:

(b+10) (b³+6b²-32b+78)

b⁴ + 6b³ + 10b³ - 32b² + 60b² + 78b - 320b + 780

= b⁴ + 16b³ + 28b² - 242b + 780

Answer Link
max2788
max2788 max2788
  • 31-03-2020

Answer:

b⁴ + 16b³ + 28b² - 242b + 780

Step-by-step explanation:

(b+10) (b³+6b²-32b+78)

b⁴ + 6b³ + 10b³ - 32b² + 60b² + 78b - 320b + 780

= b⁴ + 16b³ + 28b² - 242b + 780

Hope it helps you xD

Answer Link

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