4804397269 4804397269
  • 30-03-2020
  • Chemistry
contestada

determine the specific heat of a material if a 35g sample absorbed 96 J as it was heated from 293 K to 313 K?

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niajimenez1025
niajimenez1025 niajimenez1025
  • 06-04-2020

Answer:

0.137 J/g*C

Explanation:

Cp= k-273.15

T1= 293-273.15 = 19.85 C

T2= 313 -273.15 = 39.85 C

DeltaT= T2-T1 = 20 C

96/35x20 = 0.137 J/g*C

the "C" is supposed to be Celsius

don't ask me to further explain what you already see here

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