Step-by-step explanation:
[tex] {(x + 12)}^{2} + {(y + 13)}^{2} = 36 \\ {(x + 12)}^{2} + {(y + 13)}^{2} = {6}^{2} \\ equating \: it \: with \: \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ - h = 12 \implies \: h = - 12 \\ - k= 13 \implies \: k = - 13 \\ \therefore \: center \: = (h, \: \: k) = ( - 12, \: \: - 13) \\ \: \: \: \: {r}^{2} = {6}^{2} \implies \: radius \: (r)= 6 \: units[/tex]
