sanjukewat293 sanjukewat293

29-02-2020
Social Studies

contestada

sin2A + sin2B - sin2C = 4cosA×cosB×cosC

sin2A sin2B sin2C 4cosAcosBcosC class=

Respuesta :

mnsmurthy99 mnsmurthy99

29-02-2020

Answer:

use sin2A as 2sinAcosA and solve

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maxwellekoh maxwellekoh

29-02-2020

Answer:

Inconclusive

Explanation:

Sin2A= Sin(A+A)= SinACosA + CosAsinA=2SinACosA

Similarly

Sin2B= 2SinBCosB

Sin2C=2SinCCosC

Adding all; we cannot arrive at the expression at the right.

Answer Link

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