[tex](-2x+2)^2 [/tex] We know that: [tex]\left(a+b\right)^2=a^2+2ab+b^2[/tex] So: [tex]=\left(-2x\right)^2+2\left(-2x\right)\cdot \:2+2^2[/tex] Now: [tex]=\left(-2x\right)^2-2\cdot \:2x\cdot \:2+2^2[/tex] We apply the law of exponents and solve, so we get: [tex]=4x^2-8x+4[/tex]
