kassycasi15 kassycasi15
  • 30-01-2020
  • Mathematics
contestada

The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is:

y = (1/20)x²
x = (1/20)y²
y = -(1/20)x²

Respuesta :

calculista
calculista calculista
  • 06-02-2020

Answer:

[tex]y=\frac{1}{20}x^2[/tex]

Step-by-step explanation:

In this problem

we have

F(0,5)  and directrix at y=-5

so

Is a vertical parabola open upward

we know that

The equation of a vertical parabola in standard form is

[tex](x-h)^2=4p(y-k)[/tex]

where

p is the focal distance

(h,k) is the vertex

we have

The vertex is the origin (0,0)

and

p=5

substitute

[tex](x-0)^2=4(5)(y-0)[/tex]

[tex]x^2=20y[/tex]

[tex]y=\frac{1}{20}x^2[/tex]

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