If a Cu 2+ ion that is initially at rest accelerates through a potential difference of 12 V without friction, how much kinetic energy will it gain?

Respuesta :

Answer:

23,8eV

Explanation:

A=Uq=12 (V)* 2* 1,6*10^-19 (C)=3,84*10^-18 (J)= 23,8 (eV)