Hearts7057 Hearts7057
  • 27-01-2020
  • Mathematics
contestada

in the function fx=a(x+2)(x-3)^b, a and b are bothj integer constants and b is positive, find the value of x for f(x)=0

Respuesta :

lucianoangelini92 lucianoangelini92
  • 28-01-2020

Answer:

f(x) = 0 , when x=(-2) and x=3

Step-by-step explanation:

for a≠0 and b positive then for the function

f(x) = a*(x+2)*(x-3)ᵇ

f(x) = 0 when

1) (x+2)=0 → x=(-2)

2) (x-3)=0 → x=-3

then for x=3 and x=(-2) , f(x)=0

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