Step-by-step explanation:
[tex]\text{We know:}\\\\\sin(-\alpha)=-\sin\alpha\\\\\sin(\alpha\pm k\cdot360^o)=\sin\alpha\\\\===============================\\\\\sin(360^o-\theta)=\sin\bigg(-(\theta-360^o)\bigg)=-\sin(\theta-360^o)=-\sin\theta[/tex]
