harneetsomal3084 harneetsomal3084
  • 26-12-2019
  • Physics
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A spring that is compressed 14.5 cm from its equilibrium position stores 2.99 J of potential energy. Determine the spring constant.

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boffeemadrid
boffeemadrid boffeemadrid
  • 27-12-2019

Answer:

284.4233 N/m

Explanation:

k = Spring constant

x = Compression of spring = 14.5 cm

U = Potential energy = 2.99 J

The potential energy of a spring is given by

[tex]U=\dfrac{1}{2}kx^2[/tex]

Rearranging to get the value of k

[tex]\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 2.99}{0.145^2}\\\Rightarrow k=284.4233\ N/m[/tex]

The spring constant is 284.4233 N/m

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