Respuesta :

SvetkaChem

Answer:

-(1/3)

Step-by-step explanation:

6x² + 11x + 3 = 0

[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4*6*3}}{2*6\\}\\x_{1} = -\frac{1}{3} \\\\x_{2} = -\frac{3}{2} \\\\-\frac{1}{3} >-\frac{3}{2}[/tex]

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