jaidyn21
jaidyn21 jaidyn21
  • 30-11-2019
  • Mathematics
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Given sin 60 degrees = square root of 3 divided by 2 , find cos 60 degrees.

Given sin 60 degrees square root of 3 divided by 2 find cos 60 degrees class=

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jimrgrant1 jimrgrant1
  • 30-11-2019

Answer:

cos60° = [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 ⇒ cos x = [tex]\sqrt{1-sin^2x}[/tex]

Given

sin60° = [tex]\frac{\sqrt{3} }{2}[/tex], then

cos60° = [tex]\sqrt{1-(\frac{\sqrt{3} }{2})^2 }[/tex] = [tex]\sqrt{1-\frac{3}{4} }[/tex] = [tex]\sqrt{\frac{1}{4} }[/tex] = [tex]\frac{1}{2}[/tex]

         

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