animetrend9 animetrend9
  • 31-10-2019
  • Mathematics
contestada

write a quadartic function in standard form whose maximum value is 6 and occurs when x=-2.​

Respuesta :

jimrgrant1 jimrgrant1
  • 31-10-2019

Answer:

y = x² + 4x + 10

Step-by-step explanation:

Given the maximum value = 6 when x = - 2, then

vertex = (- 2, 6)

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier, thus

y = a(x - (- 2))² + 6 ← let a = 1

y = (x + 2)² + 6 ← equation in vertex form

Expand factor and simplify

y = x² + 4x + 4 + 6, that is

y = x² + 4x + 10 ← in standard form

Answer Link

Otras preguntas

solve the following eqution, (4p+q)3
How to solve for 6x-12+2x=3+8x-15
if a piece of DNA breaks off from a chromosome and attaches itself to a nonhomologous chromosome at another location, what type of change has occurred?
What medium did Andrew Wyeth use to paint Christina's World?
increase $60 by 15% i need help with the working out too
Write two decimals one repeating and one terminating with values between 0 and 1 then write an inequality that shows the relationship between your two decimals
What land forms start with n j y z
All of the following changed the American prairie except: a. barbed wire b. windmills and irrigation c. extermination of the buffalo d. heavy rainfall
What is the quotient of 36/12
What was the intent of the Roosevelt Corollary?