Answer:
[tex]\large\boxed{x=\dfrac{1-g}{2}}[/tex]
Step-by-step explanation:
[tex]g=-2x+1\\\\\Downarrow\\\\-2x+1=g\qquad\text{subtract 1 from both sides}\\\\-2x+1-1=g-1\\\\-2x=g-1\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2x}{-2}=\dfrac{g-1}{-2}\\\\x=\dfrac{-(1-g)}{-2}\\\\x=\dfrac{1-g}{2}[/tex]
