Answer:
[tex]\large\boxed{y-12=\dfrac{5}{6}(x+9)}[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point on a line
We have
[tex]m=\dfrac{5}{6},\ (-9,\ 12)\to x_1=-9,\ y_1=12[/tex]
Substitute:
[tex]y-12=\dfrac{5}{6}(x-(-9))\\\\y-12=\dfrac{5}{6}(x+9)[/tex]
