AsheshPatra
AsheshPatra AsheshPatra
  • 27-05-2016
  • Mathematics
contestada

evaluate:
[tex]32^{- \frac{2}{5} }




[/tex]







Respuesta :

Petroniusz
Petroniusz Petroniusz
  • 27-05-2016
[tex] 32^{- \frac{2}{5} } = ( \frac{1}{32}) ^{ \frac{2}{5} } = ( \frac{1}{32} )^{ \frac{1}{5} *2} = [ ( \frac{1}{32}) ^{ \frac{1}{5} } ]^{2} = ( \sqrt[5]{ \frac{1}{32} } ) ^{2} = ( \sqrt[5]{ \frac{1}{2}* \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} } )^{2} [/tex] = [tex] ( \frac{1}{2} )^{2} answer[/tex] 

the notebook
[tex] (32)^{- \frac{2}{5} } = ( \sqrt[5]{ \frac{1}{32} } )^{2} = ( \frac{1}{2} )^{2} = \frac{1}{4} [/tex]

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