Step-by-step explanation:
[tex]4 {x}^{2} - 16x + 8 = 0 \\ {(2x)}^{2} - 2.2x.4 + {4}^{2} - 8 = 0 \\ {(2x - 4)}^{2} - 8 = 0 \\ 2x - 4 = \sqrt{8} \: - \sqrt{8} \\ x = 2 + \sqrt{2} \\ x = 2 - \sqrt{2} [/tex]
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Plzz mark it as a brilliant answer
