antonionelson72 antonionelson72
  • 01-10-2019
  • Mathematics
contestada

find the area of a circle with a circumference of 37.68 units

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jdoe0001 jdoe0001
  • 01-10-2019

[tex]\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\ \cline{1-1} C=37.68 \end{cases}\implies 37.68=2\pi r\implies \cfrac{37.68}{2\pi }=r \\\\\\ \stackrel{assuming~\pi =3.14}{\cfrac{37.68}{2(3.14)}}=r\implies \boxed{6=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad A=\pi (6)^2\implies A=36\pi \implies A\approx 113.10[/tex]

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