nahomy699 nahomy699
  • 30-09-2019
  • Mathematics
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Sin x(cot x +tan x)= sec x

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LammettHash
LammettHash LammettHash
  • 30-09-2019

Recall the definitions of tangent and cotangent:

[tex]\tan x=\dfrac{\sin x}{\cos x}[/tex]

[tex]\cot x=\dfrac1{\tan x}=\dfrac{\cos x}{\sin x}[/tex]

Then

[tex]\sin x(\cot x+\tan x)=\sin x\left(\dfrac{\cos x}{\sin x}+\dfrac{\sin x}{\cos x}\right)=\cos x+\dfrac{\sin^2x}{\cos x}[/tex]

Recall that [tex]\sin^2x+\cos^2x=1[/tex]:

[tex]\sin x(\cot x+\tan x)=\cos x+\dfrac{1-\cos^2x}{\cos x}=\cos x+\dfrac1{\cos x}-\cos x=\dfrac1{\cos x}[/tex]

and the definition of secant,

[tex]\sec x=\dfrac1{\cos x}[/tex]

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