ainifathiha1 ainifathiha1
  • 28-09-2019
  • Mathematics
contestada

Pd).
cot x/sec x
show that -=cos ecx -sin x
​

Respuesta :

jimrgrant1 jimrgrant1
  • 28-09-2019

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• cot x = [tex]\frac{cosx}{sinx}[/tex]

• sec x = [tex]\frac{1}{cosx}[/tex] and cosec x = [tex]\frac{1}{sinx}[/tex]

Consider the left side

[tex]\frac{cotx}{secx}[/tex]

= [tex]\frac{cosx}{sinx}[/tex] × cosx

= [tex]\frac{cos^2x}{sinx}[/tex]

= [tex]\frac{1-sin^2x}{sinx}[/tex]

= [tex]\frac{1}{sinx}[/tex] - [tex]\frac{sin^2x}{sinx}[/tex]

= cosec x - sin x

= right side ⇒ verified

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