For this case we have that by definition of power properties is met:
[tex](a^m)^n=a^{m*n}[/tex]
It is also true that:
[tex]a^{-1}=\frac{1}{a^1}=\frac{1}{a}[/tex]
So, rewriting the expression we have:
[tex]7^{-32}=\frac{1}{7^{32}}[/tex]
Answer:
[tex](a^m)^n=a^{m*n}[/tex]
[tex]a^{-1}=\frac{1}{a^1}=\frac{1}{a}[/tex]
Answer:(7^-8)^-4=7^(-8)(-4)=7^32
Step-by-step explanation:
D on Edge
