Answer:
[tex]\dfrac{16x^3-37x^2-16x+37}{x^2+2}[/tex]
Step-by-step explanation:
There aren't any factors that cancel (except 3x). The best you can do is multiply it out.
[tex]\displaystyle\frac{\frac{3x^2-3}{x}}{\frac{3(x^2+2)}{16x^2-37x}}=\frac{3(x^2-1)}{x}\cdot\frac{16x^2-37x}{3(x^2+2)}\\\\=\frac{x(x^2-1)(16x-37)}{x(x^2+2)}=\frac{16x^3-37x^2-16x+37}{x^2+2}[/tex]
