Answer:
4, 1, 6.
See explanation
Step-by-step explanation:
You are given the equation
[tex]d=vt-\dfrac{1}{2}at^2[/tex]
First subtract [tex]vt[/tex] from both sides:
[tex]d-vt--\dfrac{1}{2}at^2[/tex]
and multiply the equation by -1:
[tex]vt-d=\dfrac{1}{2}at^2\ \ \ \ (1)[/tex]
Now multiply (1) by 2:
[tex]2(vt-d)=at^2\ \ \ \ \ (2)[/tex]
At last, divide by [tex]a[/tex]
[tex]t^2=\dfrac{2(vt-d)}{a}\ \ \ \ \ (3)[/tex]
