Answer:
[tex]f(g(-3))=1/7[/tex]
Step-by-step explanation:
we have
[tex]f(x)=\frac{1}{x}[/tex]
[tex]g(x)=x^{2} -2[/tex]
we know that
[tex](fg)(x)=f(g(x))=\frac{1}{x^{2} -2}[/tex]
For x=-3
substitute
[tex]f(g(-3))=\frac{1}{(-3)^{2} -2}=1/7[/tex]
therefore
[tex]f(g(-3))=1/7[/tex]
