Assuming the bus undergoes constant acceleration, it is given by:
a = (Vf-Vi)/Δt
a is the acceleration, Vf is the final velocity, Vi is the initial velocity, and Δt is the elapsed time.
Given values:
Vf = 0m/s (slows to rest)
Vi = 60m/s
Δt = 10s
Plug in the values and solve for a:
a = (0-60)/10
a = -6m/s²
The bus decelerates at a rate of 6m/s².
