Answer:
5.76 J/K
Explanation:
Mole fraction of Ne at 500 K= 50 % = 0.5 = [tex]x_A[/tex]
Mole fraction of Ar at 500 K = 50 %= 0.5 = [tex]x_B[/tex]
R = Gas constant = 8.314 J/Kmol
As mass is not given the number of moles of Ne and Ar are taken as 0.5
Entropy of mixture
[tex]\Delta_{mix}S=-R(n_Alnx_A+n_Blnx_B)\\\Rightarrow \Delta_{mix}S=-8.314(0.5ln0.5+0.5ln0.5)\\\Rightarrow \Delta_{mix}S=5.76\ J/K[/tex]
∴ Entropy of mixture is 5.76 J/K
