sanafatima2727 sanafatima2727
  • 26-06-2019
  • Physics
contestada

The current flowing through the circuit will be ?​

The current flowing through the circuit will be class=

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r3t40
r3t40 r3t40
  • 26-06-2019

[tex]

R_1=20\Omega \\

R_2=30\Omega \\

R_3=30\Omega \\

U=2V \\ \\

R_{12}=\dfrac{1}{R_1}+\dfrac{1}{R_2}=\dfrac{R_1R_2}{R_1+R_2}=15\Omega \\

R_{123}=\dfrac{R_{12}R_3}{R_{12}+R_3}=10\Omega \\

I=\dfrac{U}{R_{123}}=\boxed{0.2A}

[/tex]

Hope this helps.

r3t40

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