[tex]\bf (\stackrel{x_1}{-14}~,~\stackrel{y_1}{-10})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{18}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{18-(-10)}{12-(-14)}\implies \cfrac{18+10}{12+14}\implies \cfrac{28}{26}\implies \cfrac{14}{13}[/tex]
Answer:
28/26
Step-by-step explanation:
We can find the slope using the equation
y2-y1/x2-x1
We are give two points so lets plug them into the equation above
18-(-10)/12-(-14)
= 18+10/12+14
=28/26
