Respuesta :

znk

Answer:

[tex]\boxed {-243}\\[/tex]

Step-by-step explanation:

[tex]\begin{array}{rclr}(-3)^{-5} & = & \dfrac{1}{x}& &\\(-3)^{5} & = & x &\text{Inverted each side of the equation}\\x & = & \boxed {\textbf{{-243}}}\\\end{array}[/tex]

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