samilong51
samilong51 samilong51
  • 30-04-2019
  • Mathematics
contestada

What is the solution to the equation below?
3log4x=log432+log42
X=-8
X=-4
X=4
X=8

What is the solution to the equation below 3log4xlog432log42 X8 X4 X4 X8 class=

Respuesta :

gmany
gmany gmany
  • 08-06-2019

Answer:

[tex]\large\boxed{x=4}[/tex]

Step-by-step explanation:

[tex]3\log_4x=\log_432+\log_42\qquad\text{use}\ \log_ab^c=c\log_ab\ \text{and}\ \log_ab+\log_ac=\log_a(bc)\\\\\log_4x^3=\log_4(32\cdot2)\\\\\log_4x^3=\log_464\iff x^3=64\to x=\sqrt[3]{64}\\\\x=4[/tex]

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