Answer:
[tex]\boxed{\bold{\begin{pmatrix}x=5,\:&y=10\\ x=-3,\:&y=-6\end{pmatrix}}}[/tex]
Step By Step Explanation:
Refine:
[tex]\bold{\left(x-5\right)\left(x+3\right)=0}[/tex]
Solve [tex]\bold{\left(x-5\right)\left(x+3\right)=0: \ x=5,\:x=-3}[/tex]
For y=x2, Substitute x With 5: y = 10
For y=2x, Substitute x With -3: y = -6
Final Solutions For [tex]\bold{y=2x,\:y=x^2-15}[/tex] Are
[tex]\bold{\begin{pmatrix}x=5,\:&y=10\\ x=-3,\:&y=-6\end{pmatrix}}[/tex]
