Answer:
A
Step-by-step explanation:
Note that
x² + 12x + 36 is a perfect square → (x + 6)², hence
[tex]\sqrt{x^2+12x+36}[/tex] = [tex]\sqrt{(x+6)^2}[/tex] = (x + 6)
Hence
f(x) × g(x)
= (x + 6)(x³ - 11)
= [tex]x^{4}[/tex] - 11x + 6x³ - 66
= [tex]x^{4}[/tex] + 6x³ - 11x - 66 → A
