[tex]\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1000\\ t=\textit{elapsed time}\dotfill &12\\ h=\textit{half-life}\dotfill &5 \end{cases} \\\\\\ A=1000\left( \frac{1}{2} \right)^{\frac{12}{5}}\implies A\approx 1000\cdot 0.189\implies A\approx 189[/tex]
