ria2389
ria2389 ria2389
  • 30-03-2019
  • Mathematics
contestada

Plz help me with it

Plz help me with it class=

Respuesta :

tramserran
tramserran tramserran
  • 30-03-2019

Answer:   [tex]\bold{2\sqrt[3]{15} }[/tex]

Step-by-step explanation:

[tex]\sqrt[3]{10} \cdot \sqrt[3]{12} =\sqrt[3]{2\cdot 5\cdot 2\cdot 2\cdot 3} =2\sqrt[3]{3\cdot 5} =\boxed{2\sqrt[3]{15}}[/tex]

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