Answer:
[tex]\large\boxed{(x+3)^2+(y-2)^2=225}[/tex]
Step-by-step explanation:
The equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h, k) - center
r - radius
We have r = 15 and the center (-3, 2). Substitute:
[tex](x-(-3))^2+(y-2)^2=15^2\\\\(x+3)^2+(y-2)^2=225[/tex]
