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01-12-2018
Mathematics

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[tex] \frac{1}{4} + \frac{1}{4} + x - \frac{3}{4} [/tex]

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01-12-2018

[tex]\dfrac{1}{4}+\dfrac{1}{4}+x-\dfrac{3}{4}=\left(\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{3}{4}\right)+x=\dfrac{1+1-3}{4}+x=\dfrac{-1}{4}+x=x-\dfrac{1}{4}[/tex]

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