Case (i) : Let f(x) = cos x
-f(x) = - cos x
So, g(x) = - cos x.
f(-x) = cos (-x)
So, h(x) = cos x.
Hence, g(x) is different from h(x).
Case (ii) : Let f(x) = sin x
-f(x) = - sin x
So, g(x) = - sin x
f(-x) = sin(-x)
= - sin x
So, h(x) = - sin x.
Hence, g(x) = h(x).
