Data
---------
Velocity one = 5m/s
time one = 3.6min. =216seconds
Velocity two = 3.4m/s
time two = 2.5min. = 150seconds
Solution
-------------
Velocity ( V m/s ) of a particle is the ratio of displacement ( X meters ) to the time ( t seconds )
i.e V = X/t
therefore: X one = (V one)(t one)
= (5m/s)(216s)
=1,080m
X two = (V two)(t two)
= (3.4m/s)(150s)
= 510m
Total displacement
-----------------------------
X total = X one + X two
= 1,080m + 510m
= 1,590m
