Answer
The answer to this question is 331.59 J
Explanation
As we know Specifi Heat formula that
[tex]Q=mCpΔT[/tex]
The mass is = 72 g (72/1000 = 0.072 kg)
[tex]ΔT = 24-14 = 10^{o}C[/tex]
[tex]Cp for iron = 460.548 J/(kg^{o}C)[/tex]
Put the values in formula
[tex]Q = 0.072 * 10 * 460.548[/tex]
[tex]Q = 331.59 J[/tex]
So, absorbed heat will be 331.59 J
