edouardoromain887
edouardoromain887 edouardoromain887
  • 26-09-2018
  • Mathematics
contestada

solve for the perimeter and area of a rectangle that has a length of 4in. and a width of 2 in

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aunt2jenna aunt2jenna
  • 26-09-2018
The perimeter is either 10 (if the rectangle has two sides that are 4in and one side that is 2in) or 8 (if the rectangle has two sides that are 2in and one side that is 4in)
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whitedevil36920 whitedevil36920
  • 26-09-2018
p=4+4+2+2
=8+4
=12in

A=l×w
=4×2
=8in^2
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