[tex]\frac{(8v^3-80v^2+6)}{v-10}[/tex]
Use long division for dividing
[tex](8v^3-80v^2+6)[/tex] Here 'v' term is missing so we use 0vW
Divide [tex](8v^3-80v^2+0v+6)[/tex] by v-10 using long division
Step 1: Put 8v^2 at the top
step 2: multiply 8v^2 with v-10 and put it at the bottom
step 3: subtract it
We will get remainder 6
so quotient is [tex]8v^2[/tex]
Remainder is 6
